JEE Main & Advanced Sample Paper JEE Main Sample Paper-22

  • question_answer
    Excess of \[PC{{l}_{5}}\]  reacts with cone. \[{{H}_{2}}S{{O}_{4}}\]  giving

    A)  sulphuryl chloride

    B)  sulphurous acid

    C)  chlorosulphonic acid

    D)  thionyl chloride

    Correct Answer: A

    Solution :

    \[2PC{{l}_{5}}\,+{{H}_{2}}S{{O}_{4}}\xrightarrow{\,}2HCl+S{{O}_{2}}C{{l}_{2}}+2POC{{l}_{3}}\].


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