A) \[\sigma 2{{p}_{x}}\]
B) \[\sigma *2{{p}_{x}}\]
C) \[\pi 2{{p}_{y}}\]
D) \[\pi *2{{p}_{y}}\]
Correct Answer: C
Solution :
Boron \[({{B}_{2}}):\,{{(\sigma 1s)}^{2}}\,{{({{\sigma }^{*}}1s)}^{2}}\,{{(\sigma 2s)}^{2}}\,{{({{\sigma }^{*}}\,2s)}^{2}}({{\pi }^{2}}p_{x}^{1}\]\[=\pi 2p_{y}^{1})\,{{(\sigma {{p}_{z}})}^{0}}\]
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