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JEE Main & Advanced Sample Paper JEE Main Sample Paper-21

  • question_answer
    The end A is subjected to a tensile force F, while force applied at end B is \[\Delta \,F\] lesser than applied at end A and opposite to F. Tension at midpoint of the rod will be:

    A)  \[\frac{(F-\Delta \,F)}{2}\]                     

    B)  \[\frac{(2F-\Delta \,F)}{2}\]

    C)  \[\frac{(2F-\Delta \,F)}{4}\]        

    D)  \[F-\Delta \,F\]

    Correct Answer: B

    Solution :

    \[a=\frac{\Delta F}{M}\]. For right half part\[F-T=Ma/2\]


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