A) 28 J, 34.6 J, 24 J
B) 28 J, 0 J, 24 J
C) 24 J, 44 J, 15 J
D) None of these
Correct Answer: B
Solution :
The component of \[{{F}_{1}}\] along the direction of the displacement is \[{{F}_{1}}\cos {{30}^{o}}\] (40 N) x (0.866) = 34.6 N Hence, the work done by \[{{F}_{1}}\] is (34.6 N) (0.80 m) = 28 J. \[{{F}_{2}}\] does no work because, it has no component in the direction of the displacement. The component of \[{{F}_{3}}\] in the direction of the displacement is 30 N. Hence, the work done by \[{{F}_{3}}\] is (30 N) (0.80 m) = 24 J.You need to login to perform this action.
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