A) \[I\]
B) \[4I\]
C) \[2I\]
D) \[I\text{/}2\]
Correct Answer: B
Solution :
It\[{{y}_{1}}=a\,\sin 2\pi {{n}_{1}}\,t\]and\[{{y}_{2}}=a\,\sin 2\pi {{n}_{2}}\,t\] \[y={{y}_{1}}+{{y}_{2}}\] \[=2a\,\cos 2\pi \left( \frac{{{n}_{1}}-{{n}_{2}}}{2} \right)t\,\sin 2\pi \left( \frac{{{n}_{1}}+{{n}_{2}}}{2} \right)t\] \[A=2a\,\cos 2\pi \left( \frac{{{n}_{1}}-{{n}_{2}}}{2} \right)t\] \[\therefore \] \[{{A}_{\max }}=2a\] \[\therefore \] \[{{I}_{\max }}=4I\]
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