A) \[7.4\times {{10}^{-4}}\]KE per degree kelvin.
B) \[4.5\times {{10}^{-4}}\]KE per degree kelvin.
C) \[7.4\times {{10}^{-5}}\]KE per degree kelvin.
D) None of these
Correct Answer: A
Solution :
KE for 1 mole = 3/2 RT KE for 3 moles = 9/2 RT or \[R=\frac{2}{9T}KE=\frac{2}{9\,(300)}KE\] \[=7.4\times {{10}^{-4}}KE\]per degree kelvin.You need to login to perform this action.
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