A) \[h\rho g\]
B) \[l\rho a\]
C) \[h\rho g-l\rho a\]
D) \[h\rho g+l\rho a\]
Correct Answer: D
Solution :
\[\tan \theta =a\text{/}g\] or \[\frac{x}{l}=a\text{/}g\] \[\Rightarrow \] \[x=\frac{al}{g}\cdot \,\rho .\,g=al\rho \] \[\therefore \] \[{{P}_{B}}-{{P}_{C}}=h\rho g\] and \[{{P}_{B}}-{{P}_{A}}=h\rho g+al\rho \]
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