A) \[\frac{3}{5}\]
B) \[\frac{3}{10}\]
C) \[\frac{5}{3}\]
D) \[\frac{10}{3}\]
Correct Answer: D
Solution :
From angle bisector theorem, we get \[\frac{r}{6}=\frac{p}{q}\] \[pr=6p\] ? (i) Area of \[\Delta ADC=10\,c{{m}^{2}}\]You need to login to perform this action.
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