A) \[{{x}^{3}}{{y}^{-1}}=\frac{2}{3}{{y}^{3}}+c\]
B) \[{{x}^{2}}{{y}^{-1}}=\frac{2}{3}{{y}^{3}}+c\]
C) \[x{{y}^{-1}}=\frac{2}{3}{{y}^{3}}+c\]
D) None of these
Correct Answer: A
Solution :
\[(3y{{x}^{2}})dx+(-{{x}^{3}}-2{{y}^{4}})\,dy=0\] Integrating, we get \[{{x}^{3}}{{y}^{-1}}=\frac{2}{3}{{y}^{3}}+c\]You need to login to perform this action.
You will be redirected in
3 sec