JEE Main & Advanced Sample Paper JEE Main Sample Paper-17

  • question_answer
    A tangent drawn on the curve obtained by plotting concentration of product \[(mole\,{{L}^{-1}})\] of a first order reaction vs. time (min) at the point corresponding to time 20 minutes makes an angle of \[{{30}^{o}}\] with concentration axis. Hence, the rate of formations of product after 20 minutes will be

    A) \[0.580\,mole\,{{L}^{-1}}{{\min }^{-1}}\]              

    B)  \[1.723\,mole{{L}^{-1}}\,mi{{n}^{-1}}\]

    C)  \[0.290\,mole\,{{L}^{-1}}\,{{\min }^{-1}}\]

    D)  \[0.866\,mole\,{{L}^{-1}}{{\min }^{-1}}\]

    Correct Answer: B

    Solution :

     Tangent makes an angle of\[{{30}^{o}}\]with concentration axis so it must make an angle of \[60{}^\circ \] with the time axis (\[-\text{ve}\]direction). The slope of the tangent will be tan \[{{60}^{o}},\] i.e., 1.723.


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