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JEE Main & Advanced Sample Paper JEE Main Sample Paper-17

  • question_answer
    In YDSE, how many maxima can be obtained on a screen (including central maxima) on both sides of the central maxima if \[d=\frac{5\lambda }{2},\]where \[\lambda \] is the wavelength of light?

    A)  5                            

    B)  3

    C)  7                            

    D)  1

    Correct Answer: A

    Solution :

     In YDSE, path difference,\[\Delta x=d\sin \theta \] For maxima, \[\Delta x=n\lambda \]where \[n=0,\pm 1,\pm \,2,...\] \[\Rightarrow \]               \[\frac{5\lambda }{2}\sin \theta =n\lambda \] Since \[\sin \theta <1,\] \[\frac{2n}{5}\le 1\] \[\Rightarrow \]               \[n\le \frac{5}{2}\] i.e., \[n\] can have values \[0,\pm \,1,\pm \,\,2.\] So, a total of 5 maxima can be obtained.


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