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JEE Main & Advanced Sample Paper JEE Main Sample Paper-17

  • question_answer
    Two identical long, solid cylinders are used to conduct heat from temperature\[{{T}_{1}}\]to temperature\[{{T}_{2}}.\]Originally the cylinders are connected in series and the rate of heat transfer is H. If the cylinders are connected in parallel, then the rate of heat transfer would be

    A) \[H/4\]                

    B) \[~2H\]

    C) \[~4H\]                                

    D) \[~SH\]

    Correct Answer: C

    Solution :

     In series,\[{{R}_{s}}=2R,\] where R is the thermal resistance of one cylinder \[H=\frac{{{T}_{1}}-{{T}_{2}}}{{{R}_{s}}}=\frac{{{T}_{1}}-{{T}_{2}}}{2R}.\] In parallel, \[{{R}_{p}}=R/2.\] \[\therefore \]  \[{{H}_{p}}=\frac{{{T}_{1}}-{{T}_{2}}}{{{R}_{p}}}=\frac{{{T}_{1}}-{{T}_{2}}}{R/2}=4H\]


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