A) 1.4
B) 1.5
C) 1.53
D) 3.07
Correct Answer: B
Solution :
\[{{\text{U}}_{\text{mixture}}}\text{=}{{\text{U}}_{\text{monoatomic}}}\text{+}{{\text{U}}_{\text{diatomic}}}\] \[\therefore \]\[\frac{({{n}_{1}}+{{n}_{2}})}{{{\gamma }_{mix}}-1}=\frac{{{n}_{1}}RT}{{{\gamma }_{1}}-1}+\frac{{{n}_{2}}RT}{{{\gamma }_{2}}-1}\] \[\therefore \]\[\frac{2}{\gamma {{ & }_{mix}}^{-1}}=\frac{1}{\left( \frac{5}{3}-1 \right)}+\frac{1}{\left( \frac{7}{5}-1 \right)}\] \[\therefore \]\[{{\gamma }_{mix}}=1.5\]
You need to login to perform this action.
You will be redirected in
3 sec
