A) \[\frac{1}{3}\] times
B) 3 times
C) \[\sqrt{3}\] times
D) \[\frac{1}{\sqrt{3}}\] times
Correct Answer: D
Solution :
de-Brolie wavelength of electrons accelerated through a potential difference of V volts is \[\lambda =\frac{h}{\sqrt{2meV}}\]When accelerating voltage v is tripled, the de- Broglie wavelength becomes \[\frac{1}{\sqrt{3}}\] times.
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