A) cannot be compared
B) equal to T
C) less than T
D) more than T
Correct Answer: D
Solution :
The time-period (T) of a simple pendulum is given by \[T=2\pi \,\sqrt{\frac{I}{g}}\] \[\Rightarrow \] \[T\propto \frac{1}{\sqrt{g}}\] Let mine be a depth h below the surface of earth of radius R, then At depth \[h,\,g'\,=g\,\left( 1-\frac{h}{R} \right)\] hence, g decreases. \[\left( \because \,\frac{h}{R}<1 \right)\]
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