JEE Main & Advanced Sample Paper JEE Main Sample Paper-13

  • question_answer
    Direction (Q. Nos. 57): Electrolysis involves electronation and de-electronation al the respective electrodes. Anode of electrolytic cell is the electrode at winch de-electronation takes place whereas at cathode electronation is noticed. If two or more ions of same charge are to be electronated or de-electronated, the ion having lesser discharge potential is discharged. Discharge potential of an ion refers for \[{{E}^{o}}{{\,}_{OP}}\] or \[{{E}^{o}}_{RP}\] as the case may be. The products formed at either electrode is given in terms of Faraday?s law of electrolysis, i.e., \[W=\frac{Eit}{96500}\]
    During electrolysis of \[C{{H}_{3}}COONa(aq),\] the gas liberated at anode and cathode are respectively

    A)  \[{{H}_{2}},\,C{{O}_{2}}\] and \[{{H}_{2}}\]        

    B)  \[{{H}_{2}},\,C{{O}_{2}}\] and \[{{O}_{2}}\]

    C)  \[{{H}_{2}}\] and \[{{O}_{2}}\]                 

    D)  \[{{O}_{2}}\] and \[{{H}_{2}}\]

    Correct Answer: A

    Solution :

     At anode \[E=\frac{V}{l}=\frac{2}{0.1}=20\,V{{m}^{-1}}\] \[{{v}_{e}}={{\mu }_{e}}E=0.14\times 20=2.8\,m{{s}^{-1}}\] At cathode \[\therefore \] \[{{l}_{e}}={{n}_{e}}A\rho ve\] \[=(1.5\times {{10}^{16}})\times (1.0\times {{10}^{-4}})\times (1.6\times {{10}^{-19}})\times 2.8\] and \[=6.72\times {{10}^{-7}}A\] are liberated at anode and \[s=ut+\frac{1}{2}\,a{{t}^{2}},\] is liberated at cathode.


You need to login to perform this action.
You will be redirected in 3 sec spinner