A) \[0.98\,m{{s}^{-1}}\]
B) \[9.8\,\,m{{s}^{-1}}\]
C) \[1.96\,\,m{{s}^{-1}}\]
D) \[19.6\,\,m{{s}^{-1}}\]
Correct Answer: A
Solution :
Let m be mass of each marble and \[{{m}_{d}}\] be the mass of disc change in momentum of each marble \[(a=b=c\]. Change in momentum of nt marbles \[\alpha =\beta =\gamma ={{90}^{o}}\]. Let, the disc be balanced in mid air for a time t. Then, by impulse, momentum theorem impulse = Change in momentum. \[({{m}_{d}}g)t=2mv\times nt\] \[\alpha =\beta =\gamma \ne {{90}^{o}}\] \[{{p}_{1}}=\frac{nRT}{{{V}_{1}}}=\frac{2\times 0.0821\times 243.6}{20}=2\,\text{atm}\] \[\Delta S=nR\,\,In\,\left( \frac{{{p}_{1}}}{{{p}_{2}}} \right)\]
You need to login to perform this action.
You will be redirected in
3 sec
