A) \[C{{H}_{2}}C{{l}_{2}}\]
B) \[C{{H}_{2}}Cl\]
C) \[CHC{{l}_{3}}\]
D) \[{{C}_{2}}{{H}_{4}}C{{l}_{2}}\]
Correct Answer: B
Solution :
This problem includes conceptual mixing of determination of amount of percentage of element in organic compound and empirical formula. Quantitative determination of amount of percentage of Cl % of chlorine \[=\frac{35.5}{143.5}\times \frac{\text{mass of }AgCl}{\text{mass of the compound}}\times 100\] \[=\frac{35.5}{143.5}\times \frac{0.287}{0.099}\times 100=71.71%\] Determination of empirical formula| Symbol | Percentage | Atomic | Relativ number of atoms |
| C H Cl | 24 4.3 71.1 | 12 1 35.5 | \[\frac{24}{12}=2\] \[\frac{4.3}{1}=4.3\approx 4\] \[\frac{71.7}{35.5}\approx 2\] |
You need to login to perform this action.
You will be redirected in
3 sec
