question_answer

The sides of a triangle are \[x=2,y+1=0\]and \[x+2y=4\]. Its circumcentre is

A) (4, 0)

B) (2, -1)

C) (0, 4)    

D) (2, 3)

Correct Answer: A

Solution :

[a] : The vertices are (2, -1), (6, -1), (2, 1) forming a right angled triangle. Circumcentre is the midpoint of the hypotenuse, i.e.,\[\left( \frac{6+2}{2},\frac{1-1}{2} \right)=(4,0)\]