A) \[N{{a}_{2}}W{{O}_{3}}\]
B) \[N{{a}_{2}}W{{O}_{2}}\]
C) \[NaW{{O}_{2}}\]
D) \[NaW{{O}_{3}}\]
Correct Answer: D
Solution :
| In a unit cell, W atoms at the comer \[=\frac{1}{8}\times 8=1\] |
| O-atoms at the centre of edges \[=\frac{1}{4}\times 12=3\] |
| Na-atoms at the centre of the cube = 1 |
| \[W:O:Na=1:3:1\] |
| Hence, formula \[=NaW{{O}_{3}}\] |
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