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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 7

  • question_answer
    The decreasing order of \[{{H}^{\bigcirc -}}\] ion donor in the Cannizaro's reaction of the following is
    I. II.
    III. IV.

    A) \[I>III>II>IV\]           

    B) \[I>II>IV>II\]

    C) \[IV>II>III>I\]  

    D)  \[IV>III>II>I\]

    Correct Answer: C

    Solution :

         [c] IV (Standard) > II (only -I of \[N{{O}_{2}}\] at m-) > III (\[-1\] & \[-R\] of \[-N{{O}_{2}}\]at p-) \[>I\](\[-I\] & - of \[-N{{O}_{2}}\] at \[-o\]]      [\[\because \]\[-I\]& \[-R\] power of \[-N{{O}_{2}}\] at \[o->-I\]& \[-R\]power of \[-N{{O}_{2}}\] at\[p-\]] [\[-R\] power of \[-N{{O}_{2}}\]at \[o-\]& \[p-\] is same but \[-I\] power at \[o->-I\]power at \[p-\]


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