JEE Main & Advanced Sample Paper JEE Main - Mock Test - 6

  • question_answer
    A uniform circular ring of radius R is fixed in plane. A particle is placed on the axis of the ring at a distance much greater than R and allowed to fall towards the ring under the influence of the Ting's gravity. The particle achieves a maximum speed v. The ring is replaced with another ring of the same (linear) mass density but radius 2R, and the experiment is repeated. What is the new maximum speed of the particle?

    A) \[\frac{1}{2}v\]                   

    B) \[\frac{1}{\sqrt{2}}v\]

    C) \[v\]      

    D) \[\sqrt{2}v\]

    Correct Answer: C

    Solution :

    [c] By energy conservation, \[-\frac{GM}{R}+\frac{1}{2}{{v}^{2}}=0\] As R is doubled, m also doubles. So, v is the same.         

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