JEE Main & Advanced Sample Paper JEE Main - Mock Test - 6

  • question_answer
    The crystal field stabilization energy (CFSE) is the highest for

    A) \[{{[Co{{F}_{4}}]}^{2-}}\]                 

    B) \[{{[Co{{(NCS)}_{4}}]}^{2-}}\]

    C) \[{{[Co{{(N{{H}_{3}})}_{6}}]}^{3+}}\]        

    D) \[{{[CoC{{l}_{4}}]}^{2-}}\]

    Correct Answer: C

    Solution :

    Higher the oxidation state of the metal, greater the crystal field splitting energy. In options [a], [b] and [d], \[Co\]is present in \[+2\] oxidation state and in [c] it is present in \[+3\] oxidation state and hence has a higher value of CFSE.

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