A) \[\frac{3}{28}\]
B) \[\frac{2}{28}\]
C) \[\frac{7}{28}\]
D) \[\frac{5}{28}\]
Correct Answer: D
Solution :
| We know a leap year is fallen within 4 years, so its probability \[=\frac{1}{4}\] |
| \[{{53}^{rd}}\]Sunday in a leap year \[=\frac{1}{4}\times \frac{2}{7}=\frac{2}{28}\] |
| Similarly probability of \[{{53}^{rd}}\] Sunday in a non-leap year \[=\frac{3}{4}\times \frac{1}{7}=\frac{3}{28}\] |
| \[\therefore \] required probability \[=\frac{2}{28}+\frac{3}{28}=\frac{5}{28}\] |
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