question_answer

The number of isomers for the complexes (X) and (Y) are, respectively, \[(X)=[Pt\,{{(gly)}_{2}}],\] \[(Y)={{[Pt\{P{{({{C}_{2}}{{H}_{5}})}_{3}}\}C{{l}_{2}}]}_{2}}\]

A) 2 and 3           

B) 3 and 3

C) 3 and 4          

D) 4 and 3

Correct Answer: A

Solution :

[a] \[{{\mathbf{[Pt}\,{{\mathbf{(gly)}}_{\mathbf{2}}}\mathbf{]}}^{\mathbf{0}}}\mathbf{:}\] It is a square planar complex of \[[M{{(AB)}_{2}}]\] type in which \[gl{{y}^{\bigcirc -}}\] ion \[(N{{H}_{2}}.C{{H}_{2}}.CO{{O}^{\Theta }})\] is an unsymmetrical bidentate ligand. this complex has two geometrical isomers viz cis and trans. \[{{\mathbf{[Pt\{P(}{{\mathbf{C}}_{\mathbf{2}}}{{\mathbf{H}}_{\mathbf{5}}}{{\mathbf{)}}_{\mathbf{3}}}\mathbf{\}C}{{\mathbf{l}}_{\mathbf{2}}}\mathbf{]}}_{\mathbf{2}}}\mathbf{:}\] It is a bridged binuclear planar complex and exists in three isomeric forms viz cis, trans and unsymmetrical.