A) \[\frac{9}{25}\]
B) \[\frac{3}{25}\]
C) \[\frac{25}{9}\]
D) \[\frac{1}{25}\]
Correct Answer: A
Solution :
[a] : Distance covered in 5th second is \[{{D}_{5}}=0+\frac{a}{2}(2\times 5-1)=\frac{9a}{2}(\because u=0)\] Distance covered in 5 seconds is \[{{S}_{5}}=0+\frac{1}{2}a\times {{5}^{2}}=\frac{25a}{2}(\because u=0)\] \[\therefore \]\[\frac{{{D}_{5}}}{{{S}_{5}}}=\frac{9}{25}\]
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