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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 4

  • question_answer
    Which of the given values is twice of the equivalent mass of the oxidising agent of the given reaction, \[S{{O}_{2}}+2{{H}_{2}}S\xrightarrow[{}]{{}}3S+2{{H}_{2}}O\]

    A) 64        

    B) 32   

    C) 16                    

    D) 48

    Correct Answer: B

    Solution :

    [b]: In the equation;\[_{S{{O}_{2}}}^{+4}\to _{S}^{0}\] \[S{{O}_{2}}\] acts as an oxidising agent, \[\text{Eq}\text{.mass}\,\text{of}\,\text{S}{{\text{O}}_{\text{2}}}\text{=}\frac{\text{Molar mass}}{\text{Change in oxidation number}}\] \[\text{=}\frac{64}{4}=16\] Twice of 16= 32


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