A) A.P.
B) G.P.
C) H.P.
D) None of these
Correct Answer: B
Solution :
[b] \[{{(ap-b)}^{2}}+{{(bp-c)}^{2}}+{{(cp-d)}^{2}}\le 0\] \[{{(ap-b)}^{2}}+{{(bp-c)}^{2}}+{{(cp-d)}^{2}}=0\] \[\Rightarrow p=\frac{b}{a}=\frac{c}{b}=\frac{d}{c}\] \[\Rightarrow \] a, b, c, d are in G.P.You need to login to perform this action.
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