A) \[{{H}_{5}}{{C}_{6}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-C{{H}_{2}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-{{C}_{6}}{{H}_{5}}\]
B) \[{{H}_{5}}{{C}_{6}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-C{{H}_{3}}\]
C) \[{{H}_{5}}{{C}_{6}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-H\]
D) Both [a] and [b]
Correct Answer: D
Solution :
Keto-enol tautomerism is shown by carbonyl compounds having a-hydrogen atom. [a] \[{{H}_{5}}{{C}_{6}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-\underset{Keto\,\,form}{\mathop{\overset{\alpha }{\mathop{C}}\,{{H}_{2}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-{{C}_{6}}{{H}_{5}}}}\,\] \[\underset{enpl\,\,form}{\mathop{{{H}_{5}}{{C}_{6}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-\underset{H}{\mathop{\underset{|}{\mathop{C}}\,}}\,=\overset{OH}{\mathop{\overset{|}{\mathop{C}}\,}}\,-{{C}_{6}}{{H}_{5}}}}\,\] [b] \[\underset{Keto\,\,form}{\mathop{{{H}_{5}}{{C}_{6}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-\overset{\alpha }{\mathop{C}}\,{{H}_{3}}}}\,\underset{enol\,\,form}{\mathop{{{H}_{5}}{{C}_{6}}-\overset{OH}{\mathop{\overset{|}{\mathop{C}}\,}}\,=C{{H}_{2}}}}\,\] [c] \[\underset{no\,\,\alpha -H\,\,atom}{\mathop{{{H}_{5}}{{C}_{6}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-H}}\,\]
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