JEE Main & Advanced Sample Paper JEE Main - Mock Test - 45

  • question_answer
    A lamp emits monochromatic green light uniformly in all directions. The lamp is 3% efficient in converting electrical power to electromagnetic waves and consumes 100 W of power. The amplitude of the electric field associated with the electromagnetic radiation at a distance of 10 m from the lamp will be

    A) \[1.34\text{ }V/m\]

    B) \[2.68\text{ }V/m\]

    C) \[5.36\text{ }V/m\]

    D) \[9.37\text{ }V/m\]

    Correct Answer: A

    Solution :

    [a] \[{{S}_{av}}=\frac{1}{2}{{\varepsilon }_{0}}cE_{0}^{2}=\frac{P}{4\pi {{R}^{2}}}\] \[\Rightarrow \,\,\,\,\,{{E}_{0}}=\sqrt{\frac{P}{2\pi {{R}^{2}}{{\varepsilon }_{0}}C}}\] \[=\sqrt{\frac{3}{2\times 3.14\times 100\times 8.85\times {{10}^{-12}}\times 3\times {{10}^{8}}}}=1.34\,V/m\]


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