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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 44

  • question_answer
    Pitch of a screw gauge is 0.5 mm and its least count is .01 mm. Calculate no. of divisions on its circular scale -

    A) 100              

    B)        25

    C) 50        

    D)        None of these

    Correct Answer: C

    Solution :

       [c] Pitch = 0.5 mm \[LC=\frac{Pitch}{No.\text{ }of\text{ }circular\text{ }scale\text{ }divisions}\] \[\therefore \] No of circular scale divisions \[=\frac{0.5}{.01}=50\]             


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