A) \[164\pm 3c{{m}^{2}}\]
B) \[163.62\pm 2.6c{{m}^{2}}\]
C) \[163.6\pm 2.6c{{m}^{2}}\]
D) \[163.62\pm 3c{{m}^{2}}\]
Correct Answer: A
Solution :
Let length and breadth of a rectangular sheet are measured by using a metre scale as \[16.2\text{ }cm\]and \[10.1\text{ }cm\] respectively. Each measurement has three significant figures. Length can be written as \[l=16.2\pm 0.1cm=16.2cm\pm 0.6%\] Similarly, the breadth b can be writen as \[b=10.1\text{ }\pm 0.1\text{ }cm=10.1\text{ }cm\pm 1%\] Area of the sheet, \[A=l\times b=163.62c{{m}^{2}}\pm 1.6%=163.62\pm 2.6c{{m}^{2}}\]Therefore, as per rule, are will have only three significant figures and error will have only one significant figure. Rounding off, we get \[A=164\pm 3c{{m}^{2}}\]
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