A) 3
B) 2
C) 1
D) Data insufficient
Correct Answer: A
Solution :
[a] m. eq. of acid = m. eq. of base \[\therefore \text{ }{{N}_{1}}{{V}_{1}}={{N}_{2}}{{V}_{2}}\] \[\frac{29.4}{\frac{98}{n}}\times 100=90\times \left( \frac{20}{40}\times \frac{1000}{500} \right)\] \[\therefore n=3\]You need to login to perform this action.
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