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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 43

  • question_answer
    \[100\text{ }c{{m}^{3}}\] of a solution of an acid (Molar Mass = 98) containing 29.4 g of the acid per litre were completely neutralized by 90.0 cm3 of aq. \[NaOH\]containing 20 g of \[NaOH\] per \[500\text{ }c{{m}^{3}}\]. The basicity of the acid is:

    A) 3                 

    B)        2

    C) 1                     

    D)        Data insufficient

    Correct Answer: A

    Solution :

    [a] m. eq. of acid = m. eq. of base \[\therefore \text{ }{{N}_{1}}{{V}_{1}}={{N}_{2}}{{V}_{2}}\] \[\frac{29.4}{\frac{98}{n}}\times 100=90\times \left( \frac{20}{40}\times \frac{1000}{500} \right)\] \[\therefore n=3\]           


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