A) \[\sqrt{2}\]
B) \[\sqrt{2}+1\]
C) \[\sqrt{2}-1\]
D) \[\sqrt{2}+2\]
Correct Answer: C
Solution :
[c] Required area \[=\int\limits_{0}^{\pi /4}{\left( cosx-sinx \right)dx}\] \[=(sinx+cosx)_{0}^{\pi /4}\] \[=\left( \frac{1}{\sqrt{2}}+\frac{1}{\sqrt{2}} \right)-(0+1)=\sqrt{2}-1\]You need to login to perform this action.
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