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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 41

  • question_answer
    One mole of an ideal gas at initial temperature T undergoes a quasi-static process during which the volume V is doubled. During the process the internal energy U obeys the equation \[U=a{{v}^{3}},\] where 'a? is a constant. The work done during the process is

    A) \[\frac{3RT}{2}\]          

    B)        \[\frac{5RT}{2}\]

    C) \[\frac{5RT}{3}\]          

    D)        \[\frac{7RT}{3}\]

    Correct Answer: D

    Solution :

    [d] \[U=a{{V}^{3}}=\frac{f}{2}nRT\] So,  \[P=c{{V}^{2}}\] \[W=\int\limits_{V}^{2V}{PdV=\frac{7C{{V}^{3}}}{3}=\frac{7RT}{3}}\]


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