JEE Main & Advanced Sample Paper JEE Main - Mock Test - 3

  • question_answer
    The equivalent conductances of two strong electrolytes at infinite dilution in \[{{H}_{2}}O\] (where  ions move freely through a solution) at \[25{}^\circ C\] are given below:  \[{{\Lambda }^{o}}_{C{{H}_{3}}COONa}=91.0Sc{{m}^{2}}/equiv\] .  \[{{\Lambda }^{o}}_{HCl}=426.2S\,c{{m}^{2}}/equiv\] What additional information/quantity one needs to calculate \[{{\Lambda }^{o}}\] of an aqueous solution of acetic acid?

    A)  \[{{\Lambda }^{o}}\] of chloroacetic acid \[(ClC{{H}_{2}}COOH)\]

    B) \[{{\Lambda }^{o}}\] of NaCl

    C)  \[{{\Lambda }^{o}}\] of  \[C{{H}_{3}}COOK\]

    D)  the limiting equivalent conductance of  \[{{H}^{+}}({{\lambda }^{o}}_{{{H}^{+}}})\] .

    Correct Answer: B

    Solution :

    [b]: According to Kohlrauschs law, the molar conductivity at infinite dilution  \[({{\Lambda }^{o}})\] for a weak electrolyte,  \[C{{H}_{3}}COOH\] is, \[{{\Lambda }^{o}}_{C{{H}_{3}}COOH}={{\Lambda }^{o}}_{C{{H}_{3}}COONa}+{{\Lambda }^{o}}_{HCl}-{{\Lambda }^{o}}_{NaCl}\] So, for calculating the value of  \[{{\Lambda }^{o}}_{C{{H}_{3}}COOH'}\] value of  \[{{\Lambda }^{o}}_{NaCl'}\] should also be known.


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