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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 3

  • question_answer
    In a face-centred cubic arrangement of A and B atoms in which A atoms are at the corners of the unit cell and B atoms are at the face centres, one of the A atoms is missing from one corner in unit cell. The simplest formula of the compound is

    A) \[{{A}_{7}}{{B}_{3}}\]                       

    B) \[A{{B}_{3}}\]

    C) \[{{A}_{7}}{{B}_{24}}\]         

    D) \[{{A}_{8/7}}{{B}_{3}}\]

    Correct Answer: C

    Solution :

    [c] : No. of atoms of A from corners of unit cell = 7/8 No. of atoms of B from faces of unit cell = 3 Thus, A : B = 7/8 : 3 or 7 : 24. Thus, formula is \[{{A}_{7}}{{B}_{24}}\].


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