A) \[1/2\]
B) \[1/\sqrt{2}\]
C) \[\sqrt{3}\]
D) \[3/2\]
Correct Answer: A
Solution :
[a] \[\left| \vec{p}-\vec{q} \right|=\vec{p}.\vec{q}\] \[\Rightarrow \,\,\,\,\,\,\,{{\left| {\vec{p}} \right|}^{2}}+{{\left| {\vec{q}} \right|}^{2}}-2\vec{p}.\vec{q}=\sqrt{2}\,\,\cos \theta \] \[\Rightarrow \,\,\,\,\,\,\,\,\cos \theta =\frac{1}{\sqrt{2}}\] \[\therefore \] Area \[=\frac{1}{2}\left| {\vec{p}} \right|.\left| {\vec{q}} \right|\,\,\,\sin \theta =\frac{1}{2}\]You need to login to perform this action.
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