A) \[\frac{1}{2}m\frac{v}{{{t}_{1}}}{{t}^{2}}\]
B) \[m\frac{v}{{{t}_{1}}}{{t}^{2}}\]
C) \[\frac{1}{2}{{\left( \frac{mv}{{{t}_{1}}} \right)}^{2}}{{t}^{2}}\]
D) \[\frac{1}{2}m\frac{{{v}^{2}}}{t_{2}^{1}}{{t}^{2}}\]
Correct Answer: D
Solution :
[d] Work done \[=F\times s=ma\times \frac{1}{2}a{{t}^{2}}\] \[\left[ from\,\,s=ut+\frac{1}{2}a{{t}^{2}} \right]\] \[\therefore \,\,\,\,\,\,\,\,\,\,\,\,\,\,W=\frac{1}{2}m{{a}^{2}}{{t}^{2}}=\frac{1}{2}m{{\left( \frac{v}{{{t}_{1}}} \right)}^{2}}{{t}^{2}}\] \[\left[ As\,\,\,s=\frac{v}{{{t}_{1}}} \right]\]
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