JEE Main & Advanced Sample Paper JEE Main - Mock Test - 37

  • question_answer
    The graph shows the behaviour of a length of wire in the region for which the substance obeys Hooke?s law. P and Q represent  

    A) \[\operatorname{P} = applied force, Q = extension\]

    B) \[\operatorname{P} = extension, Q = applied force\]

    C) \[\operatorname{P} = extension, Q = stored elastic energy\]

    D) \[\operatorname{P} = stored elastic energy, Q = extension\]

    Correct Answer: C

    Solution :

    Graph between applied force and extension will be straight line because in elastic range, Applied force \[\propto \] extension but the graph between extension and stored elastic energy will be parabolic in nature As \[\operatorname{U}=\,\,\frac{1}{2}\,k{{x}^{2}}\,\,or U \,\propto {{x}^{2}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner