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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 34

  • question_answer
    The introduction of a metal plate between the plates of a parallel plate eapacitor increases its capacitance by \[4.5\] times. If d is the separation of the two plates of the capacitor, the thickness of the metal plate introduced is

    A) \[d/3\]                    

    B)       \[5d/9\]                 

    C)   \[7d/9\]            

    D)        \[d\]

    Correct Answer: C

    Solution :

    [c] Let initial capacitance be \[C=\frac{{{\varepsilon }_{0}}A}{d}.\] \[{{C}_{final}}=\frac{{{\varepsilon }_{0}}A}{d'}=\frac{9}{2}\frac{{{\varepsilon }_{0}}A}{d}\] \[d'=\frac{2}{9}d\] Let the thickness of metal plate be t.             \[d-t=d'\]             \[t=\frac{7}{9}d\]   


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