A) Increases
B) Decreases
C) Becomes zero
D) Does not change
Correct Answer: A
Solution :
s-character increases with increase in bond angle.| Hybridisation | \[s\,%\] | Angle |
| sp | 50 | \[180{}^\circ \] |
| \[{{\operatorname{sp}}^{3}}\] | 33.3 | \[120{}^\circ \] |
| \[{{\operatorname{sp}}^{3}}\] | 25 | \[109{}^\circ .28'\] |
| \[{{\operatorname{sp}}^{3}}d\] | 20 | \[90{}^\circ \,\,and\,\,120{}^\circ \] |
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