2. Sample Papers
  3. JEE Main & Advanced

JEE Main & Advanced Sample Paper JEE Main - Mock Test - 33

  • question_answer
    Measure of two quantities along with the precision of respective measuring instrument is \[A=2.5\,m{{s}^{-1}}\pm 0.5m{{s}^{-1}}\] \[B=0.10s\pm 0.01s\] The value of AB will be

    A) \[(0.25\pm 0.08)m\]

    B)        \[(0.25\pm 0.5)m\]

    C) \[(0.25\pm 0.05)m\]   

    D)      \[(0.25\pm 0.135)m\]

    Correct Answer: A

    Solution :

    [a] Error in AB \[=\pm \left( \frac{\Delta A}{A}+\frac{\Delta B}{B} \right)AB=\pm \left[ \frac{0.5}{2.5}+\frac{0.01}{0.10} \right][0.25]\] \[=\pm 0.075=\pm 0.08\] Therefore, \[AB=(0.25\pm 0.08)m\]


You need to login to perform this action.
You will be redirected in 3 sec spinner