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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 33

  • question_answer
    A particle of charge q, mass m starts moving from the origin under the action of an electric field \[\vec{E}={{E}_{0}}\hat{i}\]and magnetic field\[\vec{B}={{B}_{0}}\hat{k}\]. Its velocity at \[(x,0,0)\] is \[6\hat{i}+8\hat{j}\]. The value of x is    

    A) \[\frac{25m}{q{{E}_{0}}}\]      

    B)        \[\frac{100\,m}{q{{B}_{0}}}\]

    C) \[\frac{50\,m}{q{{E}_{0}}}\]    

    D)        \[\frac{14\,m}{q{{E}_{0}}}\]

    Correct Answer: C

    Solution :

    [c] Applying work energy theorem, \[q{{E}_{0}}x=\frac{1}{2}m{{(10)}^{2}};\,\,\,x=\frac{50m}{q{{E}_{0}}}\]


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