A) Boiling the mixture with \[N{{H}_{4}}Cl\] and adding \[HgC{{l}_{2}}\]
B) Boiling the mixture with \[N{{H}_{4}}OH\] and adding \[HgC{{l}_{2}}\]
C) Boiling the mixture and evaporate to half the solution and adding \[{{H}_{2}}{{C}_{2}}{{O}_{4}}\]
D) Boiling the mixture with cone. \[HN{{O}_{3}}\] and adding \[C{{l}_{2}}\] water.
Correct Answer: A
Solution :
[a] Boil the mixture with \[N{{H}_{4}}Cl,\,\,N{{O}_{2}}^{\Theta }\] is decomposed as\[{{N}_{2}}\]. \[NaN{{O}_{2}}+N{{H}_{4}}Cl\xrightarrow{\Delta }NaCl+{{N}_{2}}\uparrow +2{{H}_{2}}O\] (ii) Add \[HgC{{l}_{2}},\]which removes \[{{I}^{\Theta }}\] as \[Hg{{I}_{2}}\] \[HgC{{l}_{2}}+2{{I}^{\Theta }}\xrightarrow{{}}\underset{orange\,\,ppt}{\mathop{Hg{{I}_{2}}\downarrow }}\,+2C{{l}^{\Theta }}\]
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