| (I) \[\overset{\Theta }{\mathop{O}}\,H\] ion attacks at the \[(C=O)\] group of . |
| (II) \[\overset{\Theta }{\mathop{O}}\,H\]ion attacks at \[(C=O)\]group of . |
(III) The \[{{H}^{\Theta }}\] ion transfer takes place from |
(IV) The \[{{H}^{\Theta }}\] ion transfer takes place from  |
A) I
B) III
C) I, III
D) II, IV
Correct Answer: C
Solution :
[c] is more reactive aldehyde Since \[-N{{O}_{2}}\] group at p-position is more Electron with drawing than \[-N{{O}_{2}}\] group at w-position. Hence, \[\overset{\Theta }{\mathop{O}}\,H\] attacks at \[(C=O)\] group of [a] and \[{{H}^{\Theta }}\] ion transfer occurs form the dianion of [A]
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