A) \[\underset{Orange}{\mathop{N{{a}_{2}}C{{r}_{2}}{{O}_{7}}}}\,+2N{{H}_{4}}OH\xrightarrow{{}}(A)\underset{Orange}{\mathop{\xrightarrow{\Delta }}}\,\]
B) \[2N{{H}_{3}}+3CaOC{{l}_{2}}\xrightarrow{{}}\]
C) \[8N{{H}_{3}}+3C{{l}_{2}}\xrightarrow{{}}\]
D) \[2N{{H}_{3}}+NaOCl\xrightarrow{\Delta }\]
Correct Answer: D
Solution :
[d] (1) \[\underset{orange\,\,(A)}{\mathop{{{(N{{H}_{4}})}_{2}}C{{r}_{2}}{{O}_{7}}}}\,\xrightarrow{\Delta }{{N}_{2}}+\underset{green}{\mathop{C{{r}_{2}}{{O}_{3}}}}\,+{{H}_{2}}O\] (2) \[2N{{H}_{3}}+3CaOC{{l}_{2}}\xrightarrow{{}}3CaC{{l}_{2}}+{{N}_{2}}+3{{H}_{2}}O\] (3) \[8N{{H}_{3}}+C{{l}_{2}}\xrightarrow{{}}6N{{H}_{4}}Cl+{{N}_{2}}\] (4) \[2N{{H}_{3}}+NaOCl\xrightarrow{\Delta }NaCl+{{H}_{2}}O+\underset{Hydrazine}{\mathop{{{H}_{2}}N-N{{H}_{2}}}}\,\]
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