A) \[-\frac{3GM}{a}\]
B) \[-\frac{2GM}{a}\]
C) \[-\frac{GM}{a}\]
D) \[-\frac{4GM}{a}\]
Correct Answer: A
Solution :
[a] : Gravitational potential due to the shell of radius a at any point inside it \[=-\frac{GM}{a}\] Gravitational potential due to the particle at the centre at a point P distant \[\frac{a}{2}\] from the centre\[=-\frac{GM}{a/2}=-\frac{2GM}{a}\] \[\therefore \]Net gravitational potential at P \[=-\frac{GM}{a}-\frac{2GM}{a}=-\frac{3GM}{a}\]
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