A) \[\frac{1}{4}\]
B) \[\frac{\sqrt{3}}{4}\]
C) \[\frac{1}{2}\]
D) \[\frac{1}{8}\]
Correct Answer: D
Solution :
[d]: As\[{{\varepsilon }_{rms}}=\frac{{{\varepsilon }_{0}}}{\sqrt{2}}=\frac{(1/\sqrt{2})}{\sqrt{2}}=\frac{1}{2}V,\] \[{{I}_{rms}}=\frac{{{I}_{0}}}{\sqrt{2}}=\frac{(1/\sqrt{2})}{\sqrt{2}}=\frac{1}{2}A,\] and\[\cos \phi =\cos \pi /3=\frac{1}{2}\] \[{{P}_{av}}={{\varepsilon }_{rms}}{{I}_{rms}}\cos \phi =\left( \frac{1}{2} \right)\left( \frac{1}{2} \right)\left( \frac{1}{2} \right)=\frac{1}{8}W\]
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